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8n^2-11n+3=0
a = 8; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·8·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-5}{2*8}=\frac{6}{16} =3/8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+5}{2*8}=\frac{16}{16} =1 $
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